1Low-pass: 10kΩ + 100nF
Inputs
Result
fc = 1/(2π×10000×0.0000001) = 1/(0.00628) = 159.15Hz. τ = 10000×0.0000001 = 1ms.
Cutoff Frequency
159.15 Hz
Type
Low-Pass
e.g. 0.0000001 = 100nF
Cutoff Frequency
159.15 Hz
Filter
Low-Pass
Time Const
1.000 ms
Formula: fc = 1 / (2πRC)
-3dB at cutoff, -20dB/decade rolloff
Inputs
Result
fc = 1/(2π×10000×0.0000001) = 1/(0.00628) = 159.15Hz. τ = 10000×0.0000001 = 1ms.
Inputs
Result
R = 1/(2π×1000×0.0000001) = 1/(0.000628) = 1,592Ω. Use 1.5kΩ or 1.6kΩ standard value.
fc = 1/(2πRC). For R=10kΩ and C=100nF: fc = 1/(2π×10000×0.0000001) = 159.15Hz. This is the -3dB point where output is 70.7% of input.
| R | C | Cutoff Frequency | Use Case |
|---|---|---|---|
| 10kΩ | 100nF | 159 Hz | Audio sub-bass |
| 10kΩ | 10nF | 1.59 kHz | Audio treble |
| 1kΩ | 100nF | 1.59 kHz | Signal filtering |
| 100kΩ | 1nF | 1.59 kHz | High-impedance |
Low-pass passes frequencies below fc and attenuates above. High-pass passes above fc and blocks below. Same formula, different capacitor placement in the circuit.
A single RC filter has -20dB/decade (6dB/octave) rolloff. This means for every 10x frequency increase past fc, the signal drops by 20dB (factor of 10 in voltage).
Set cutoff at half the sampling rate (Nyquist). For 44.1kHz sampling: fc = 22.05kHz. A 2nd-order filter (-40dB/decade) is minimum; 4th order preferred for audio.
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Last Updated: Mar 20, 2026
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