Feed Rate
73.3 in/min
RPM
12,223
MRR
0.917 in³/m
Feed Rate
73.3
inches per minute
RPM
12,223
Chip Load
0.003"
MRR
0.917 in³/m
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Inputs
Result
RPM = 800*12/(3.14*0.25) = 12,223. Feed = 12,223 * 2 * 0.003 = 73.3 in/min.
Inputs
Result
RPM = 100*12/(3.14*0.5) = 764. Feed = 764 * 4 * 0.002 = 6.1 in/min.
RPM = SFM × 12 / (π × tool diameter). For aluminum at 800 SFM with a 0.25" end mill: RPM = 800 × 12 / (3.14 × 0.25) = 12,223 RPM.
| Material | SFM | Chip Load (0.25") | RPM (0.25") |
|---|---|---|---|
| Aluminum | 800 | 0.003" | 12,223 |
| Mild Steel | 100 | 0.002" | 1,528 |
| Stainless | 65 | 0.0015" | 993 |
| Hardwood | 600 | 0.008" | 9,167 |
Feed rate (in/min) = RPM × flutes × chip load. A 2-flute end mill at 12,223 RPM with 0.003" chip load: 12,223 × 2 × 0.003 = 73.3 in/min.
When width of cut is less than 50% of tool diameter, the actual chip is thinner than programmed. Increase feed rate to maintain proper chip thickness and prevent rubbing.
MRR = width of cut × depth of cut × feed rate, in cubic inches per minute. Higher MRR = faster machining but more spindle power needed.
Electronics, mechanical, and everyday tools
Last Updated: Jun 18, 2026
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