1Find voltage: 2A through 6Ω
Inputs
Result
V = I × R = 2 × 6 = 12V. P = V × I = 12 × 2 = 24W.
Voltage
12.000 V
V
12.000 V
P
24.000 W
Voltage
12.000 V
Voltage
12.000 V
Current
2.000 A
Resistance
6.000 Ω
Power
24.000 W
Inputs
Result
V = I × R = 2 × 6 = 12V. P = V × I = 12 × 2 = 24W.
Inputs
Result
R = V / I = 5 / 0.02 = 250Ω. P = 5 × 0.02 = 0.1W = 100mW.
Ohm's law states V = I × R: voltage equals current times resistance. Combined with P = V × I, you can solve for any electrical quantity from two knowns.
| Known Values | Formula for V | Formula for I | Formula for R | Formula for P |
|---|---|---|---|---|
| V and I | — | — | V/I | V×I |
| V and R | — | V/R | — | V²/R |
| I and R | I×R | — | — | I²×R |
| P and I | P/I | — | P/I² | — |
Divide voltage by current: R = V / I. For example, 12V across a component drawing 2A means R = 12/2 = 6Ω.
Power (watts) = voltage × current. A 12V supply delivering 2A provides 24W. Power also equals I²R or V²/R.
Ohm's law applies to linear (ohmic) devices like resistors. Non-linear components like diodes, transistors, and LEDs don't follow V=IR directly—they have voltage-current curves instead.
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Last Updated: Mar 20, 2026
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